Question

A body starts from rest with uniform acceleration. Its velocity after 2n second is `v_(0)`. The displacement of the body in last n second is `(3v_(0)n)/(beta)`. Determine the value of `beta`?

Answer 1

Correct Answer - 4
`v_(0)=2na" "a=(v_(0))/(2n), s=(1)/(2)(2n)^(2)-(1)/(2)an^(2)`
`=(3)/(2)an^(2)" "=(3)/(2)(v_(0))/(2n)n^(2)=(3v_(0)n)/(4)`