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Two stones are thrown vertically upwards with the same velocity of `49 m//s`. If they are thrown one after the other with a time lapse of 3 second, height at which they collide is
A. 58.8 m
B. 111.5 m
C. 117.6 m
D. 122.5 m

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1 Answer

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Correct Answer - B
`h=(u^(2))/(2g)-(g t^(2))/(8)`

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