Question

Two stones are thrown vertically upwards with the same velocity of `49 m//s`. If they are thrown one after the other with a time lapse of 3 second, height at which they collide is
A. 58.8 m
B. 111.5 m
C. 117.6 m
D. 122.5 m

Answer 1

Correct Answer - B
`h=(u^(2))/(2g)-(g t^(2))/(8)`