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0 votes
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in Physics by (76.5k points)
A ball is projected vertically upwards with a velocity of `25ms^(-1)` from the bottom of a tower. A boy who is standing at the top of a tower is unable to catch the ball when it passes him in the upward direction. But the ball again reaches him after 3 sec when it is falling. Now the boy catches it then the height of the tower is `(g=10ms^(-2))`
A. 5m
B. 10 m
C. 15 m
D. 20 m

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1 Answer

0 votes
by (76.7k points)
Correct Answer - D
`t=(2v)/(g),v^(2)u^(2)=-2gh`

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