Question

A man starts chasing his dog 10 second after the latter runs along a straight track at a unifrom acceleration of `0.5 m//s^(2)`. The track is 2 km long after which it bends aways into the field. What will be the minimum constant speed of the man so that he may catch the dog before the bend in the track ?
A. 1.50 km/hr
B. 40 m/s
C. 90 km/hr
D. 20 m/s

Answer 1

Correct Answer - C
`2.0 = (1)/(2) xx a xx t^(2)` Where `a = (1)/(2) m//s^(2)`
For man `2.0 = v xx t`