Question

A car is moving along a straight (OP). It moves from `O to P` in `18 seconds` amd retuns from `P to Q` in 6 seconds`, where `OP=360 m` and `OQ=240 m What are the car the average velcoty and average speed of the car in going (a) from `Oto P` and back to `Q` ?
A. velocity
B. acceleration
C. work done
D. The averge velocity of the car in going for a particle in a given interval of time represents

Answer 1

Correct Answer - D
From O to P and back to Q
Average speed = Path length / Time interval = OP + PQ/`delta t`
= (360 + 120)m/24 s = `20 m s^(-1)`
Average velocity = Displacement / Time interval = 240 m /24 s = `10 m s^(_1)`
From O to P and come back to O
Average speed = 360 m + 360 m / 36 s = `20 m s^(-1)`
Average velocity = 0 m/36 s = zero