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In ΔABC, ∠ACB = 90° and CD ⊥ AB.

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In ΔABC, ∠ACB = 90° and CD ⊥ AB.

Prove that : BC2/AC2 = BD/AD

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In ΔCDB,

∠1 + ∠2 + ∠3 = 180o

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In ΔABC, ∠B = 90° and BD ⊥ AC.
asked Sep 14, 2018 in Mathematics by AsutoshSahni (54.5k points)

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