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A particle of mass `0.5 kg` is displaced from position `vec r_(1)(2,3,1)` to`vec r_(2)(4,3,2)` by applying a force of magnitude `30 N` which is acting along `(hati + hatj + hatk)`. The work done by the force is
A. `10 sqrt(3) J`
B. `30 sqrt(3)`
C. 30 J
D. 40 J

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Best answer
Correct Answer - B
`F_(x) = F cos alpha, F_(y) = F cos beta, F_(z) = F cos gamma, W = F.S`.

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