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In a tank filled with a liquid of refractive index `5//3`, a point source of light is placed `2 m` below the surface of water. To cut off all light coming out of water from the source, what should be the minimum diameter of a disc, which should be placed over the source on the surface of water ?

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Correct Answer - 3
Here, `mu = 5//3, OC = 2 cm, AB = 2 AC = ?`
To cut off all light coming from the source out of water, total internal reflection should occur at `A` and `B`, for which
`mu = (1)/(sin C) = (5)/(3) , sin C = (3)/(5) = sin theta`
`:. tan theta = (4)/(5) = (AC)/(OC) , AC = (4)/(5) xx 2 = (8)/(5) m`
`AB = 2AC = 2 xx (8)/(5) m = (16)/(5) m = 3.2 m`
The correct integral answer is `3 m`.
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