Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
53 views
in Physics by (76.7k points)
closed by
A particle move in a straight line with retardation proportional to its displacement its loss of kinectic energy for any displacement `x` is proportional to
A. `x^(2)`
B. `e^(x)`
C. x
D. `log_(e)x`

1 Answer

0 votes
by (76.5k points)
selected by
 
Best answer
Correct Answer - A
`V(dv)/(dx)=-Kx, [(v^(2))/2]_(u)^(v)=-[(kx^(2))/2]_(0)^(x)`
`V^(2)-u^(2)=-Kx^(2)`
`1/2 m u^(2)-1/2 mV^(2)=1/2 mKx^(2)`
Loss `alpha x^(2)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...