Question

If KE of a body increases by `300%`, by what `%` will the linear momentum of the body increase?
A. `100 %`
B. `150 %`
C. `sqrt(300) %`
D. `175 %`

Answer 1

Correct Answer - A
For percentage change , use
`= (("Final value")/("Initial value") -1) xx 100%`
`K_(1) = K,K_(2) = K (1 + (300)/(100)) = 4 K`
`(p_(2))/(p_(1)) = sqrt((K_(2))/(K_(1)) = 2`
`((p_(2))/(p_(1)) - 1) xx 100 = 100 %`