Question

As student performs an experiment for determine of `g[=(4pi^(2)L)/(T^(2))]. L approx 1m`, and has commits an error of `Delta L` for `T` he tajes the teime of `n` osciollations wityh the stop watch of least count `Delta T`. For which of the following data the measurement of `g` will be most accurate?
A. `Delta L = 0.5, DeltaT = 0.1n = 20`
B. `Delta L = 0.5, DeltaT = 0.1n = 50`
C. `Delta L = 0.5, DeltaT = 0.01n = 20`
D. `Delta L = 0.5, DeltaT = 0.05n = 50`

Answer 1

Correct Answer - D
`(Delta g)/(g) = (Delta l)/(l) + 2(Delta T)/(T)` (`Delta l` and `DeltaT` are least and the number of readings are maximum)