Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
780 views
in Physics by (76.7k points)
closed by
If ideal diatomic gas follows the process, as shown in graph, where `T` is temperature in kelvin and `V` is volume `(m^(3))`, then molar heat capacity for this process will be [in terms of gas constant `R]`:
image
A. `(7R)/(2)`
B. `5R`
C. `(19R)/(6)`
D. `(11R)/(2)`

1 Answer

0 votes
by (76.5k points)
selected by
 
Best answer
Correct Answer - C
`C = Cv +(R )/(1-eta) ……..(i)`
`T^(2) V^(-3) =` constant `, PV = nRT`
`P^(2)V^(2)V^(-3) =` constat `, P^(2)V^(-1) =` constant
`PV^(-1//2) =` constant
`N =- 1//2`
`C = (5R)/(2) +(2R)/(3) =(19R)/(6)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...