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Two moles of helium gas are taken over the cycle ABCDA, as shown in the P-T diagram
image
Assuming the gas to be ideal the work done on the gas in taking it form A to B is :
A. `200R`
B. `300R`
C. `400R`
D. `500R`

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Correct Answer - C
`n ("moles") = 2`
`A` to `B` is isobaric process
`W_(AB) = P DeltaV = nR DeltaT`
`= (2) (R )(200) = 400R`
`W_(AB) = 400R`
`(W_(AB))_("on the gas") =- 400R`

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