Correct Answer - A::B::D
If `u` is the initial speed and `theta` the angle of projection.Then `v_(y)= u sin theta-"gt"` i.e., `x-t` graph is a straight line passing through the origin. `y=(u sin theta)t-1/2 "gt"^(2)`
i.e., `y-t`graph is parpbola i.e., `v_(x)-t` graph is a straight line parallel to `t`-axis.