Correct Answer - C
`U=2-20x+5x^(2)`
`F=-(dU)/(dx)=20-10x`
At equilibrium position `,F=0`
`20-10x=0`
`rArr x=2`
Since particle is released at `x=-3` , therefore amplitude of particle is 5 .
It will oscillate x = 2 with an amplitude of 5.
`:.` maximum value of x will be 7.