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A ring of mass 5 kg sliding on a frictionless vertical rod connected by a clock B of mass 10 kg by the help of a massless string.
Then, at the equilibrium of the system, the value of `theta` is
image
A. `30^(@)`
B. `60^(@)`
C. `90^(@)`
D. `0^(@)`

1 Answer

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Best answer
Correct Answer - B
For ring,
From force diagram of ring,
`T cos theta = m_(1)g " "...(i)`
For block B,
mg = T
`T cos theta = m_(1) g`
`mg cos theta = m_(1)g`
`therefore " "cos theta=(m_(1))/(m)=(5)/(10)=(1)/(2)`
`implies " "theta=60^(@)`
image

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