Correct Answer - B
Let the mass of disc without hole =m
The mass of cut out hole of radius `R/2` is `m/4`
`:. m-m/4=M` or `m=4/3M`
Moment of inertia of given body about axis passing through O
`=MI` of complete disc -MI of cut out hole .
`=1/2((4M)/3)R^(2)-[1/2(M/3)(R/2)^(2)+M/3(R/2)^(2)]=13/24 MR^(2)`