Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
987 views
in Physics by (86.6k points)
closed by
A thin uniform rigid rod of mass `m` and length `l` is in mechanical equilibrium under the constraints of horizontal and vertical rough surfaces. Then select correct option(s):
image
A. the net torque of normal reaction about `O` is equal to `(mgl)/2 cos theta`
B. the net torque due to friction about `O` is zero
C. the net torque due to normal reaction is numerically equal to the net torque due to the frictional force about the `CM` of the rod
D. all of the above

1 Answer

0 votes
by (86.0k points)
selected by
 
Best answer
Correct Answer - A::B::C::D
image
`N_(1)=mg-f_(2).....(1), N_(2)=f_(1).....(2)`
Now taking moment about `A`
`N_(2)xxlsin theta+f_(2)xxlcos theta=mgl/2xxcos theta......(3)`
Take moment about point `B`
`N_(1)xxIcos theta=mgxxl/2 cos theta+f_(1)xxl sin theta....(4)`
`tau_(0)`(of normals)=
`N_(1)l cos theta+N_(2)xxl sin theta=(mg)/2`
`l cos theta+(mg)/2 cot theta=2mglcos theta//2`
`B,C &D`are easily explain

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...