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When the number of turns in a toroidal coil is doubled, then the value of magnetic flux density will becomes-
A. four times
B. eight times
C. half
D. double

1 Answer

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Best answer
Correct Answer - D
`Bxx2piR=mu_(0) xxN.i`
`B=(mu_(0).i)/(2piR).N`
`B prop N`
So the magnetic field will be double.

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