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Two springs of spring constants `1500N//m` and `3000N//m` respectively are streched by the same force. The potential energy gained by the two springs will be in the ratio

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From `W = (F^(2))/(2K)`, if force `F` is same on two springs `W alpha (1)/(K)` or `U alpha (1)/(K), (U_(1))/(U_(2)) = (K_(2))/(K_(1)) = (3000)/(1500) = (2)/(1)`

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