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Soapy water drips from a capillary tube. When the drop breaks away, the diameter of its neck is D. The mass of the drop is `m`. Find the surface tension of soapy? Water?
A. `(mg)/(pi^(2)D)`
B. `(mg)/(piD^(2))`
C. `(mg)/(piD)`
D. `(mg)/(2piD)`

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Correct Answer - C
When the drop breaks away from the capillary weight of the drop `=` force of surface tensiton,
or `mg=piDxxT or T=(mg)/(piD)`

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