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The sum of first 16 terms of the AP 10, 6, 2, …. is (a) 320 (b) -320 (c) -352 (d) -400

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The sum of first 16 terms of the AP 10, 6, 2, …. is 

(a) 320 (b) -320 (c) -352 (d) -400

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Here, a = 10, d = (6-10) = -4 and n = 16

Hence, the sum of the first 16 terms of the given AP is -320.

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