Correct Answer - B
Let the ball A is thrown vertically upwards with speed u and ball B is thrown vertically downwards with the same speed u.
After reaching the highest point, A comes back to its point of projection with the same speed u in the downward direction, then velocity of A on reaching the grounds is
`v_(A)^(2)=u^(2)+2ghorv_(A)=sqrt(u^(2)+2gh)" ..."....(i)` and that of B on reaching the ground is
`v_(B)^(2)=u^(2)+2ghorv_(B)=sqrt(u^(2)+2gh)" ".........(ii)`
From eqns (i) and (ii), we get `v_(A)=v_(B)`