Question

The least count of a stopwatch is 0.2 s. A student found the time of 25 oscillations of a simple pendulum to be 50 second. What will be the percentage error in the measurement of time?
A. `0.2%`
B. `0.4%`
C. `0.01%`
D. `1.5%`

Answer 1

Correct Answer - b
The error can be equal to the least count of the stopwatch i.e. 0.2 s = `Deltat` and t = 50 s
`therefore` Percentage error `=((Deltat)/(t))xx100`
`=(0.2)/(50)xx100=0.4%`