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A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it ?
A. A screw gauge having 100 divisions in the circular scale and pitch as 1 mm
B. A screw gauge having 50 divisions in the circular scale and pitch as 1 mm
C. A meter scale
D. A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm

1 Answer

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Best answer
Correct Answer - D
Least count of vernier callipers is 0.01 cm
Hence it matches with the reading.

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