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A particle has displacement of `12m` towards east and `5 m` towards north then `6 m` vertically upward. The sum of these displacements is-

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A particle has displacement of `12m` towards east and `5 m` towards north then `6 m` vertically upward. The sum of these displacements is-
A. 12 m
B. 10.04 m
C. 14.31 m
D. 23 m
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Correct Answer - C
Displacement=`sqrt(12^(2)+5^(2)+6^(2))`
`=sqrt(144+25+36)=sqrt(205)=14.31 m`
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