Correct Answer - B
Using the relation for volume,
`V` = Length `xx` Breadth `xx` Thickness
=12`xx`6`xx`2.45=176.4 `cm^(3)`
`V` =1.764`xx` `10^(2)` `cm^(3)`
The minimum number of significant figure is 1 in breadth. Hence, the volume will contain only one significant figure. Therefore, `V=2xx10^(2)cm^(3)`.