Question

A particle executing SHM of amplitude 4 cm and `T=4 s` .The time taken by it to move from positive extreme position to half the amplitude is
A. 1 s
B. `(1)/(3)` s
C. `(2)/(3)` s
D. `sqrt((2)/(3))` s

Answer 1

Correct Answer - C
(c)Equation of motion , `y= a"cos"omegat`
`implies(a)/(2)=a "cos"omegatimpliesomegat=(pi)/(3)`
`implies (2pit)/(T)=(pi)/(3)impliest=((pi)/(3)xxT)/(2pi)=(4)/(3xx2)=(2)/(3) s`