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Find the sum of given Arithmetic Progression `4+8+ 12+....+ 64`
A. 464
B. 540
C. 544
D. 646

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Correct Answer - 3
Here a=4, d =4, n=16 So, = `(n)/(2)` [First term + last term]= `(16)/(2)[4+ 64]= 8(68)= 544`

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