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An air bubble of 1 cm radius is rising at a steady rate of `2.00ms^-1` through a liquid of density `1.5gcm^-3`. Neglect density of air. If `g=1000cms^-2`, then the coeffieciet of viscosity of the liquid is

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Correct Answer - `35.55` poise
`v = (2r^(2))/(9eta)(rho_(0) - rho_(a))g`
`0.5 = (2)/(9eta) xx 0.8 xx 100`
`eta = (320)/(9) = 35.55` poise

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