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A ring of diameter 0.4 m and of mass 10 kg is rotating about its geometrical axis at the rate of 35 ratation/second. Find the moment of intertia.

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A ring of diameter 0.4 m and of mass 10 kg is rotating about its geometrical axis at the rate of 35 ratation/second. Find the moment of intertia.
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Moment of intertia of the ring about its axis is
`I=MR^(2)`
`I=10xx(0.2)^(2)=10xx0.04 =0.4 "kg-m"^(2)`.
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