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50 g of copper is heated to increase its temperature by `10^@C`. If the same quantity of heat is given to `10g` of water, the rise in its temperature is (specific heat of copper`=420J//kg^(@)//C`)
A. `5^(@)C`
B. `6^(@)C`
C. `7^(@)C`
D. `8^(@)C`

1 Answer

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Correct Answer - A
Same amount of heat is supplied to copper and water.
So, `m_(C)c_(C)DeltaT_(c)= m_(W)c_(W)DeltaT`
`rArr` `DeltaT_(W) = (m_(C)c_(C)(DeltaT)_(c))/(m_(W)c_(W))`
=`(50 xx 10^(-3) xx 420 xx 10)/(10 xx 10^(-3) xx 4200)`= 5^(@)C`

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