Correct Answer - C
`R_(AB) = R_(CD)=R`(say)
Length of semicircle = `pil`
Resistance of semicircle = `piR` as `Ralphal`
`R_(BC) = (piR)/2`(in parallel)
Heat current, H = `(100-0)/(R+R+(pi)/2.R)=28/R` units
Now, `theta_(C) - 0^(@)` = HR = `28^(@)`C
`theta_(C)` = `28^(@)`C