Question

A student performs an experiment for determination of ` g [ = ( 4 pi^(2) L)/(T^(2)) ] , L ~~ 1m` , and he commits an error of `Delta L`. For `T` he takes the time of `n` oscillations with the stop watch of least count ` Delta T` . For which of the following data , the measurement of `g` will be most accurate ?
A. `DeltaL=0.5, DeltaT=0.1, n=20`
B. `DeltaL=0.5, DeltaT=0.1, n=50`
C. `DeltaL=0.5, DeltaT=0.01, n=20`
D. `DeltaL=0.5, DeltaT=0.05, n=50`

Answer 1

Correct Answer - d
`(Deltag)/g=(Deltal)/(l)+2(DeltaT)/(n T)`
(`Deltal` and `DeltaT` are least, and the number of resdings are maximum.)