Correct Answer - B
When string is not cut, let `F_(s)` be the restoring force within the spring
For spring B: `T=mg`
For body A: `F_(s)=2mg+T=2mg+mg=3mg`
When the string is cut, body B will fall freely therefore, its acceleration is `a_(B)=g`
For body A: `(2m)a_(A)=F_(s)-(2m)g=3mg-2mg=mg`
`:. a_(A)=g/2`