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A block `B` is pushed momentarily along a horizontal surface with an initial velocity `v` . If mu is the coefficient of sliding friction between `B` and the surface, block `B` will come to rest after a time:
image
A. `(v)/(g mu)`
B. `(g mu)/(v)`
C. `(g)/(v)`
D. `(v)/(g)`

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Correct Answer - A
`mu = (f)/(N) = (ma)/(mg) = (a)/(g)`
`implies` Retardation , a = `mu` g
Using , v = u + at , 0 = v `- mu` gt
`t = (v)/(mu g)`

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