A ball is dropped from the top of a building. The ball takes `0.5s` to fall the `3m` length of a window some distance from the to of the building. If the speed of the ball at the top and at the bottom of the window are `v_(T)` and `v_(T)` respectively, then `(g=9.8m//s^(2))`
A. `v_(T)+v_(B)=12ms^(-1)`
B. `v_(T)-v_(B)=4.9ms^(-1)`
C. `v_(B)+v(T)=1ms^(-1)`
D. `(v_(B))/(v_(T))=2`
