
\(AB = 40 m\)
\(\angle PAD = 30°\)
\(\therefore \angle BAD = 90° - 30° = 60°\)
In \(\triangle ABD,\)
\(\tan 60° = \frac{BD}{AB}\)
⇒ \(\sqrt 3 = \frac{BD}{40}\)
⇒ \(BD = 40\sqrt3\)
In \(\triangle BCD,\)
\(\tan 60° = \frac{CD}{BD}\)
⇒ \(\sqrt 3 = \frac{CD}{40\sqrt 3}\)
⇒ \(CD = (40\sqrt 3). \sqrt 3\)
⇒ \(CD = 40\times 3 = 120\)
\(\therefore \) Height of chimney = 120 m.