Correct Answer - A::B::C::D
Hence` angle PRQ=pi//2` and points P, Q, R lie on the circle with PQ as diameter.
Also, `PQ=5.`
Now, the maximum area of the triangle is
`Delta_(max)=(1)/(2)(5)((5)/(2))=6.25`
For area = 5, we have four symmetrical positions of point R (shown as `R_(1), R_(2),R_(3), R_(4)`).
For area = 6.25, we have exactly two points.
For area = 7, no such points exist.