Correct Answer - C::D
`[2x]=[x]+[x+(1)/(2)]`
` :. [2x]-2[x]=[x+(1)/(2)]-[x]`
`=[[x]+{x}+(1)/(2)]-[x]`
` =[{x}+(1)/(2)]`
If ` {x} ge (1)/(2) implies {x} +(1)/(2)ge 1implies [{x} +(1)/(2)]=1 implieslambda =1`
If `{x} lt (1)/(2) implies {x} +(1)/(2)lt 1implies [{x} +(1)/(2)]=0 implieslambda =0`