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`[2x]-2[x]=lambda` where [.] represents greatest integer function and {.} represents fractional part of a real number then
A. `lambda=1 AA x in R`
B. `lambda=0 AA x in R`
C. `lambda =1 AA {x} ge (1)/(2) `
D. `lambda =0 AA {x} lt (1)/(2)`

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Correct Answer - C::D
`[2x]=[x]+[x+(1)/(2)]`
` :. [2x]-2[x]=[x+(1)/(2)]-[x]`
`=[[x]+{x}+(1)/(2)]-[x]`
` =[{x}+(1)/(2)]`
If ` {x} ge (1)/(2) implies {x} +(1)/(2)ge 1implies [{x} +(1)/(2)]=1 implieslambda =1`
If `{x} lt (1)/(2) implies {x} +(1)/(2)lt 1implies [{x} +(1)/(2)]=0 implieslambda =0`

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