Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
123 views
in Circles by (93.6k points)
closed by
Tangents `PA and PB` are drawn to the circle `x^2 +y^2=8` from any arbitrary point P on the line `x+y =4`. The locus of mid-point of chord of contact AB is
A. `x^(2)+y^(2) -2x -2y = 0`
B. `x^(2) +y^(2) +2x +2y = 0`
C. `x^(2) +y^(2) - 2x +2y = 0`
D. `x^(2) +y^(2) +2x - 2y= 0`

1 Answer

0 votes
by (94.6k points)
selected by
 
Best answer
Correct Answer - A
Let `P(a,4-a)`.
image
The equation of chord of contact AB is
`xa +y (4-a) =8` (i)
Also, equation of chord AB whose mid-points is `M(h,k)` is
`hx + ky = h^(2) +k^(2)` (ii) (using `T = S_(1))`
Since (i) and (ii) are identical, on comparing the coefficients, we get
`(a)/(h) =(4-a)/(k) = (8)/(h^(2) +k^(2)) =(a+4-a)/(h+k) =(4)/(h+k)`
`rArr 4(h^(2)+k^(2)) =8(h+k)`
Hence, locus of `M(h,k)` is `x^(2) +y^(2) -2x -2y =0`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...