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The activity of a sample of radioactive element `.^(100)A` is 6.02 curie. Its decay constant is `3.7 xx 10^(4) s^(-1)`. The initial mass of the sample will be:
A. `10^(-14) g`
B. `10^(-6) g`
C. `10^(-15) g`
D. `10^(-3) g`

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Correct Answer - c
Activtiy `= lambda x (w)/(At. Wt) xx 6.023 xx 10^(23)`
`6.02 xx 3.7 xx 10^(10) = 3.7 xx 10^(4) xx (w)/(100) xx 6.023 xx 10^(23)`
`w = 10^(-15) g`

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