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The reaction `._(3)^(7)Li + ._(1)^(1)H rarr ._(4)^(7)Be + ._(0)^(1)n` is endothermic. Assuming that Li nuclei is free and at rest. If the minimum kinetic energy (in keV) of incident proton so that this reaction occurs is 470N KeV, where N is an integer find N ? Take Q value of this reaction as -1645 keV.

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Correct Answer - `0004`
Energy available `=(1)/(2) mu v_(rel)^(2).=Q` value.
`(1)/(2)xx(7xx1)/(7+1)xxv_(rel)^(2)=Q` value.
`rArr (1)/(2)xxv_(rel)^(2)=Qxx(8)/(7)`
`K_(i)1645xx(8)/(7)=1880`KeV

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