Question

Silver crystallizes in fcc lattic. If the edge length of the cell is `4.07 xx 10^(-8) cm` and density is `10.5 g cm^(-3)`. Calculate the atomic mass of silver.

Answer 1

`d=(ZM)/(a^(3) xx Na)`
`rArr" "M = (d xx a^(3) xx Na)/Z = (10.5 xx(4.07)^(3)xx10^(-24)xx6.02 xx 10^(23))/4 = 106.5391 g//mol`.