Question

`[HXeO_4]^(-) + OH^(-) to [X] + [Y] + O_2 +H_2O`
The products [X] and [Y] in unbalanced reaction are:
A. `[XeO_6]^(4-) & Xe`
B. `[XeO_6]^(4-) & XeO_3`
C. `XeO_3 & Xe`
D. `H_2XeO_4 & Xe`

Answer 1

Correct Answer - A
`2[HXeO_4]^(-) + 2OH^(-) to [XeO_6]^(4-) + Xe + O_2 + 2H_2O`