Correct Answer - C
The circle is
`x^(2)+y^(2)-4x-8y-5=0`
Its centre is `(2,4)` and radius is `sqrt(4+16+5)=5`
If the circle intersects the line `3x-4y=m` at two distinct points, then the length of the perpendicular from the centre is less than the radius, i.e.,
`(|6-16-m|)/(5) lt5`
`implies |10+m| lt25`
`implies 25 lt m +10lt25`
`implies -35ltmlt15`