Given ellipse is `(x^(2))/(16)+(y^(2))/(9)=1`
Let the equation of tangent by `y=mx+sqrt(16m^(2)+9)`
It passes through the point (2,3) .
`:. 3=2m+sqrt(16m^(2)+9)`
`rArr (3-2m)^(2)=16m^(2)+9`
`rArr12m^(2)+12m=0`
`rArrm=0,-1`
Therefore, equation of tangents are
`y-3=-1(x-2) and y-3=0`
`o y=-x+5 and y=3`