Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
316 views
in Ellipse by (91.7k points)
closed by
A cruve is respresented by `C=21x^(2)-6xy+29y^(2)+6x-58y-151=0`
The lengths of axes are
A. `6,2 sqrt(6)`
B. `5,2sqrt(5)`
C. `4,4sqrt(5)`
D. none of these

1 Answer

0 votes
by (93.1k points)
selected by
 
Best answer
`24x^(2)-6xy+29y+6x-58y-151=0`
`2(x-3y+3)^(2)+2(3x+y-1)^(2)=180`
or `((x-3y+3)^(2))/(60)+((3x+y-1)^(2))/(90)=1`
or `((x-3y+3)/(sqrt(1+3^(2))sqrt(6)))^(2)+((3x+y-1)/(3sqrt(1+3^(2))))=1`
Thus, C is an ellipse whose lengths of axes are `6,2sqrt(6)`.
The minor and the major axes are `x-3y+3=0 and 3x+y-1=0`, respectively.
Their point of intersection gives the center of the center of the conic. Therefore, Center `-=(o,1)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...