Correct Answer - A
Given ten numbers are
10, 22, 26, 29, 34, x, 42, 67, 70, y
and their mean `=42`
` therefore (10+ 22+ 26+ 29+ 34+ x+ 42+ 67+ 70+ y)/(10)=42`
`rArr (300+x+y)/(10)=42`
`rArr x+y=120 " …(i)" `
and their median (arranged numbers are in increasing order)`= 35`
`rArr (34+x)/(2)=35`
`rArr 34+x=70`
`rArr x=36`
On substituting `x=36` in Eq. (i), we get
`36+y=120`
`rArr y=84`
` therefore (y)/(x)=(84)/(36)=(7)/(3)`