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The number of neutrons in the parent nucleus which gives `N^(14) " on " beta-`emission and the parent nucleus is
A. `8, C^(14)`
B. `6, C^(12)`
C. `4, C^(13)`
D. None of these

1 Answer

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Best answer
Correct Answer - A
`._(6)C^(14) rarr ._(7)N^(14) + ._(+1)e^(0)`
No. of neutrons in `C^(14) = 14 - 6 = 8`

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